Question

P(A’uB’)=3/8, P(A)=1/3, P(B’)=1/6 find P(AuB)
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Answer 1

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Answer 2

Step-by-step explanation:

P(A)= 1/3 

P(B)= 1/4 

Now, P(AUB) = 11/12 

=> P(A)+ P(B) - P(A∩B) = 11/12 

=> P(A∩B) = ( 1/3 + 3/4 ) - 11/12 = 2/12 = 1/6 

Therefore, 

P(B/A)= P(A∩B) / P(A)

          = (1/6) / (1/3) 

          = 1/2