Question

P and have co-ordinates (-1, 2) and (6, 3) respectively. Reflect P in the X
axis to P'. Calculate the length of P'Q. Leave your answer in the root form.
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Answer 1

Answer:

Reflection of p in the x axis is (-1,-2)=p'

p'Q,=(-1,-2)(6,3)

p'Q=Square root (6+1)^2+(3+2)^2

square root(74)