P AND Q ARE ANY TWO POINTS LYING ON THE SIDES DC AND AD RESPECTIVELY OF THE PARALLELOGRAM ABCD SHOW THAT area (∆APB=BQC)
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since APB and ABCD lie in same parallel line and same base AB.... So,
ar(APB)=1/2ar(ABCD). ..........(1)
CBQ and ABCD lie in same parallel line and same base BC.....So,
ar(CBQ)=1/2ar(ABCD). .........(2)
From eq. (1) and (2) , we get
ar(APB)=ar(CBQ)
ar(APB)=1/2ar(ABCD). ..........(1)
CBQ and ABCD lie in same parallel line and same base BC.....So,
ar(CBQ)=1/2ar(ABCD). .........(2)
From eq. (1) and (2) , we get
ar(APB)=ar(CBQ)
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