Question

P and Q are are two elements that form P2Q3 and PQ2. If 0.15 mole of P2Q3 weigh 15.9g and 0.15 mole of PQ2 weigh 9.3g.what are the atomic weights of P and Q​

Answer 1

The 2 compounds formed by P and Q = P₂Q₃ , PQ₂

let the atomic weight of P = x

let the atomic weight of Q = y

molecular mass of  P₂Q₃ = 2x + 3y

molecular mass of PQ₂= x+ 2y

We know,

no. of moles = mass/ molecular mass

0.15 = 15.9/ 2x+ 3y

2x+ 3y = 15.9/0.15

2x+ 3y = 106------------(1)

0.15 = 9.3/ x+2y

x+2y = 9.3/ 0.15

x+2y= 62-------------(2)

using elimination method to find x and y

(1)-(2)*2

2x+3y- 2x-4y= 106- 124

y = 18

x = 26

hence, weight of P = 26g

            weight of Q =18g

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Answer 2

Explanation:

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