P and q are the end points of a diameter of a circle having its (2,4). If the coordinates of P are (-6,5), find the coordinates of the point q
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Since 2,4 is the mid point,
-6+x/2=2
-6+x=4
x=10
5+y/2=4
5+y=8
y=3
Therefore the coordinates of q are(10,3)
-6+x/2=2
-6+x=4
x=10
5+y/2=4
5+y=8
y=3
Therefore the coordinates of q are(10,3)
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