Question

P and Q are the points with co-ordinates (2, -1) and ( - 3, 4). Find the co-ordinates of the
point R such that PR = PQ.

Answer 1

given

P and Q are the points with co-ordinates (2, -1) and ( - 3, 4).

the point P which is in mid point satisfy the condition PR=PQ

Let R be(x,y)

=》》(2,-1)=((x-3)/2,(4+y)/2)

=》》4=x-3 and -2=4+y

=》》x=7 and y=-6

also the point satisfy PR=PQ

so R is a point that lies on the circle passing through P and Q

so the distance between R and P = distance between P and Q

●the center of the required circle is P since it is equii distance with R and Q

●the radius of required circle is distance between P and Q

PQ=5√2

so the locus of point R is

(x-2)^2+(y+1)^2=50

all the points on the above circle satisfy the condition PR=PQ

also the above point found (using mid point) lies on the circle

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Answer 2

Answer:

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Step-by-step explanation: