P (AuCnB) is equivalent to?
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If A and b are two different events then, P(A U B) = P(A) + P(B) - P(A ∩ B). Consider the Venn diagram. P(A U B) is the probability of the sum of all sample points in A U B. Now P(A) + P(B) is the sum of probabilities of sample points in A and in B.
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