Question

P can complete a piece of work, working alone in 3 days.q can complete the work in 5 days.if they work in alternate days the work would be completed in least number of days if

Answer 1

P completes one - third of the work in a day
Q completes one-fifth of the work in a day
They work alternate days. So in every 2 days they complete: 1/3 +1/5 = 8/15 of the work
Let us consider 2 days as a single unit.
So, we need 15/8 such units to complete the work. That is 1.875
1.5 unit means 3 days and 1.875 is higher than 1.5
So we need minimum 4 days

Answer 2

Answer:

Least Number of days required is 4 days of work.

Explanation:

What is Unitary Methord ?

The unitary method involves calculating the value of a single unit, from which we can calculate the values of the necessary number of units.

P's one day work = $\frac{1}{3} \ part$

Q's one day work = $\frac{1}{5} \ part$

If they Work alternatively (P+Q)'s 2 days work = $\frac{8}{15}$ parts

So finish the work time required = $2 * \frac{15}{8} = 3.75$ days

Least Number of days required is 4 days of work

To learn more about Unitary Methord refer to :

https://brainly.in/question/12383836?referrer=searchResults

https://brainly.in/question/9475359?referrer=searchResults

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