Question

P Cube + 27 factorise​

Answer 1

p³+ 27

(P) ³ + (3) ³

a³+b³= (a+b) (a²- ab + b²)

(P+3) (p²-3p+27)

Hope this helps!

Answer 2

hey!

p^3 + 27

p^3+3^3

identity used = a^3+b^3 = (a+b) ( a^2+b^2-ab)

let p = a

b=3

(p+3)(p^2+3^2-3×p)

(p+3) (p^2+9-3p)

hence, ans is (p+3)(p^2+9-3p)