Question

P=Fv+Av^3p check the dimensional validity of the equation

Answer 1

Explanation:

so the given P=FV+AV^3

THE FORMULA FOR F= MLT^-2 (ma) V=LT^-1 (DISTANCE/TIME)

a= l*b(L^2)

A) THE DIMENSIONAL FORMULA OF

POWER IS

FORMULA =FORCE/AREA

SO MLT^-2/L^2 =ML^-1T^-2

here if we want to add two variables say 3x +4x here only if x is the same variable we can add so the dimension of fv must be equal to av^3 suppose if they ask u 2 find the dimension of some constant by giving some equation plz keep ths idea in ur mind

b) p=ML^-1T^-2 in Lhs and in rhs fv =( MLT^-2) (LT^-1)=ML^T^-3

AV^3= (L^2) (LT^-1)^3=L^5T^-3

so c here acc to the idea i said before only if de dimensions of all the 3 quantities we can say that they are dimensionally crt so here it is not dimensionally valid