Question

P is a point equidistant from two lines
intersecting at O. Prove that OP
bisects the angle between the two lines.​

Answer 1

Answer:

Step-by-step explanation:

You are given that lines l and m intersect each other at A.

Let PB is perpendicular on l and

PC⊥m. It is given that PB=PC.

You need to show that ∠PAB=∠PAC.

Let us consider △PAB and △PAC. In these two triangles,

PB=PC (Given)

∠PBA=∠PCA=90  

∘

 (Given)

PA=PA (Common side)

So, △PAB≅△PAC (RHS rule)

So, ∠PAB=∠PAC(CPCT)