Question

P is a point in the interior of angle AOB. PM and PQ are drawn perpendiculars to OA and OB and PM=PQ. Show that P lies on the bisector of angle AOB.​

Answer 1

Answer:

As the lines PL and PM are perpendicular to OA and AB respectively the angles PLO and PMO are both 90° and form a linear pair. ... So, angles AOP and BOP are equal which proves that OP is the bisector of angle AOB

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