Question

P is a point on the line segment joining A(3,4) and B (6,-2) such that 5AP =2BP. find the coordinates of Point.

Answer 1

Answer:

27/7,16/7

Step-by-step explanation:

Given

A=(3,4)

B=(6,-2)

5AP = 2BP

Let P(x,y) be the point on the line

Formula ((mx2+nx1 ) / m+n ) , ((my2+ny1) / m+n)

5AP = 2BP  

AP / BP = 2/5-

A(3,4) is (x1,y1)           B(6,-2) is x2,y2

m = 2 n = 5  

Substitute in formula

[[(2(6) + 5(3)] /5+2 ) , ([2(-2) + 5(4)] / 5+2) ]

[[12+15] / 7 , [-4+20] / 7]

[27/7 , 16/7 ]

So the coordinates of P are [ 27/7 , 16/7]

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