Question

P is a point on x axis and q is on y axis both are equidistant from the points (7,6) & (3,4) distance between p and q is

Answer 1

Answer:

I hope this answer help you. ..

Answer 2

Answer:

15 root 5 / 2

Step-by-step explanation:

Solution

Let the coordinates of P be (x, 0)(x, 0)  and of Q be (0, y)(0, y) , then

(x−7)2+62=(x−3)2+42⇒x=152(x−7)2+62=(x−3)2+42⇒x=152  and

72+(y−6)2=32+(y−4)2⇒y=1572+(y−6)2=32+(y−4)2⇒y=15

So, coordinates of P are (152, 0)(152, 0)  and of Q are (0, 15)(0, 15)

⇒PQ=(152)2+(15)2−−−−−−−−