Question

P is an integer. P>883. If P-7 is multiple of 11. Then largest number that will always divide (P+4)(P+15) is

Answer 1

someone can make find this 456789 3456 the answer

Answer 2

Answer:

242

Step-by-step explanation

P is an integer>883.

P-7 is a multiple of 11=>there exist a positive integer a such that

P-7=11 a=>P=11 a+7

(P+4)(P+15)=(11 a+7+4)(11 a+7+15)

                      =(11 a+11)(11 a+22)

                      =121(a+1)(a+2)

As a is a positive integer therefore (a+1)(a+2) is divisible by 2.Hence (P+4)(P+15) is divisible by 121*2=242