Question

P is any point inside the triangle ABC such that the perpendicular drawn from P on AB and AC are equal . Prove that AP is the bisector of angle BAC

Answer 1

Step-by-step explanation:

BP bisects <ABC

Given: P is any point in the angle ABC such that the perpendiculars drawn from P on AB and BC are equal. ... Hence corresponding angles in the two triangles will be equal. So <ABP = <PBC. Therefore BP bisects <ABC.