Math, asked by Ishika3115, 1 year ago

P is any point on side bc of a triangle abc. Pm parallel to ba and pn parallel to ca. Mn produced meets bc produced at q. Prove that qp=qb*qc

Answers

Answered by Anonymous
0

If AB = QR, BC = PR and CA = PQ, then ... D is a point on the side BC of a ∆ ABC such that AD bisects ∠BAC. ..... If the line through P, parallel to BA meet BC

Answered by itzraone
1

Answer:

If AB = QR, BC = PR and CA = PQ, then ... D is a point on the side BC of a ∆ ABC such that AD bisects ∠BAC. ..... If the line through P, parallel to BA meet BC ...

Using this formula..

Yu can sokve itt..

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