Question

P is midpt on side BC of triangle AND if area of triangle APC = 16 CM square fond area of triangle ABP

Answer 1

Soluion:

Concept:

Area of a triangle

=(1/2) x base x height

Given:

P is the midpoint of side BC.

Then, BP=PC...........(1)

Let AD be the altitude drawn from A to BC.

Area of triangle APC = 16 cm²

(1/2)(PC)(AD)=16

(PC)(AD)=32..........(2)

Now,

Area of triangle ABP

=(1/2)(BP)(AD)

=(1/2)(PC)(AD) (by using (1))

=(1/2)(32) (by using (2))

= 16 cm²