Question

Reena is 6 years older than his brother ajay. If the sum of their ages be 28 years. Find their present ages?

Answer 1

Solutions :-

Let the age Ajay be x
Reena's age = x + 6

Given : Sum of their ages be 28 years.


According to the question,

=> x + x + 6 = 28
=> 2x + 6 = 28
=> 2x = 28 - 6
=> 2x = 22
=> x = 22/2 = 11


Hence,
Age of Ajay = x = 11 years
Age of Reena = x + 6 = 11 + 6 = 17 years

Answer 2

$\underline{\underline{\Huge\mathfrak{Solution ;}}}$

$<b>$Dear ,

Your Answer is ;

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• Step by Step Explanation ;-
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• Assuming Ajay's age as "y".
• And Reena's Age = y + 6

Given that ;-
• Sum of their ages = 28 years.

Now ,
ATQ ;-

$= > y + y + 6 = 28$

$= > 2y + 6 = 28$

$= > 2y = 28 - 6$

$= > 2y = 22$

$= > y = \frac{22}{2} = 11$

$= > y = 11 \: years$

Therefore ,
• Ajay's Age = y = 11 years.
• Reena's Age = 11 + 6 = 17 years.

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