Question

p=log(px-y),p=dy/dx solve​

Answer 1

If p is constant,

dp/dx=0 and d/dx[log(px-y)]=(p-dy/dx)/(px-y),

assuming logs to base e,

So (p-dy/dx)/(px-y)=0

and assuming that px-y is not zero,

p-dy/dx=0 and so dy/dx=p.