Question

p(m) = m² – 3m + 1, find the value of p(1) and p(–1).

Answer 1

Dear Student.

P(m) = $m^{2} -\frac{3}{1} m+1$  

P(1) = $1^{2} -\frac{3}{1}*1+1$

P(1)= 1 -3+1

P(1)=2-3

P(1)=-1

P(-1) = $(-1)^{2} -\frac{3}{1}*(-1)+1$  

P(-1) = 1+3+1

P(-1)=2+3

P(-1)=5

Hope it helps

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Answer 2

Solution :

Given p(m) = m² - 3m + 1

i ) p(1) = 1² - 3( 1 ) + 1

= 1 - 3 + 1

= 2 - 3

= -1

ii ) p( -1 ) = ( -1 )² - 3( -1 ) + 1

= 1 + 3 + 1

= 5

Therefore ,

p(1) = -1 ,

p(-1) = 5

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