P(m)=m3+2m2_m+10then p(a)+p(-a)=?
Answers
Answered by
14
Step-by-step explanation:
P(m) = m^3 + 2m^2 - m + 10
P(a) = a^3 + 2a^2 - a + 10
P(-a) = (-a)^3 + 2(-a)^2 -(-a) + 10
= (-a)^3 + 2a^2 + a + 10
P(a) + P(-a) = 4a^2 + 20
Answered by
40
Answer:
★ Question★
p [m] = m³+2m³-m+10 then find p [a]+p[-1]=?
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† solution †
p [m] = m³+2m³-m+10
:⟹p[a]=a³+2a^2- a+10
:⟹p[-a]= -a³+2a^2+a+10
:⟹p [a]+[p-1]
:⟹a³+2a^2-a+10-a³+2a^2+a+10
:⟹4a^2+20
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*Answer*
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:⟹ p [a]+[p-1]=4a^2+20 ꪜ
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