p(n)=x^3+3x^2-7x+6.find p (1),p(2)
Answers
Answered by
0
Answer:
p(1) = 3
p(2) = 12
Step-by-step explanation:
p(x) = x³ + 3x² - 7x + 6
p(1) = (1)³ + 3(1)² - 7(1) + 6
= 1 + 3 - 7 + 6
= 1 + 3 + 6 - 7
= 10 - 7
= 3
Hence p(1) = 3 for p(x)
p(2) = (2)³ + 3(2)² - 7(2) + 6
= 8 + 3(4) - 14 + 6
= 8 + 12 + 6 - 14
= 26 - 14
= 12
Hence p(2) = 12 for p(x)
hope it helps.
Answered by
3
Step-by-step explanation:
Answer:
p(1) = 3
p(2) = 12
Step-by-step explanation:
p(x) = x³ + 3x² - 7x + 6
p(1) = (1)³ + 3(1)² - 7(1) + 6
= 1 + 3 - 7 + 6
= 1 + 3 + 6 - 7
= 10 - 7
= 3
Hence p(1) = 3 for p(x)
p(2) = (2)³ + 3(2)² - 7(2) + 6
= 8 + 3(4) - 14 + 6
= 8 + 12 + 6 - 14
= 26 - 14
= 12
Hence p(2) = 12 for p(x)
hope it helps.
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