Question

p(n)=x^3+3x^2-7x+6.find p (1),p(2)​

Answer 1

Answer:

p(1) = 3

p(2) = 12

Step-by-step explanation:

p(x) = x³ + 3x² - 7x + 6

p(1) = (1)³ + 3(1)² - 7(1) + 6

= 1 + 3 - 7 + 6

= 1 + 3 + 6 - 7

= 10 - 7

= 3

Hence p(1) = 3 for p(x)

p(2) = (2)³ + 3(2)² - 7(2) + 6

= 8 + 3(4) - 14 + 6

= 8 + 12 + 6 - 14

= 26 - 14

= 12

Hence p(2) = 12 for p(x)

hope it helps.

Answer 2

Step-by-step explanation:

Answer:

p(1) = 3

p(2) = 12

Step-by-step explanation:

p(x) = x³ + 3x² - 7x + 6

p(1) = (1)³ + 3(1)² - 7(1) + 6

= 1 + 3 - 7 + 6

= 1 + 3 + 6 - 7

= 10 - 7

= 3

Hence p(1) = 3 for p(x)

p(2) = (2)³ + 3(2)² - 7(2) + 6

= 8 + 3(4) - 14 + 6

= 8 + 12 + 6 - 14

= 26 - 14

= 12

Hence p(2) = 12 for p(x)

hope it helps.