Question

P+q=√13, p-q=√5 pq=?
Give me answer

Answer 1

Step-by-step explanation:

(p+q)^2= p^2+q^2+2pq

13=p^2+q^2+2pq -i

(p-q)^2= p^2+q^2- 2pq

5=p^2+q^2- 2pq

p^2+q^2+2pq+p^2+q^2- 2pq= 13+5

2 (p^2+q^2)=18

p^2+q^2=9

p^2+q^2+2pq=13

9+2pq = 13

2pq =4

pq=2