Math, asked by shivendra222chauhan, 2 months ago

(p/q)^3x×2=(q/p)^2-x​

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Answered by vatikasingh79
2

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Answered by abhishekshibu9267
0

Answer:

(\frac{p}{q})^{3x *2}=(\frac{q}{p})^{({2-x})}\\\\(\frac{p}{q})^{6x}=(\frac{q}{p})^{({2-x})}\\\\(\frac{p}{q})^{6x}=[(\frac{p}{q})^-]^{({2-x})}\\\\(\frac{p}{q})^{6x}=(\frac{p}{q})^-^{({2-x})}\\\\(\frac{p}{q})^{6x}=(\frac{p}{q})^-^{{2+x}}\\\\6x=-2+x\\\\x= \frac{-2}{6}\\\\x=\frac{-1}{3}

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