P,Q and R are respectively the mid points of sides BC,CA and AB of triangle ABC. if AP and BQ intersect at G then AG + BG + CG =
Answers
Answered by
1
if P,Q and R are mid points of sides BC,CA and AB of Δ ABC then AG + BG + CG = (2/3) (AP + BQ + CR)
Step-by-step explanation:
P,Q and R are respectively the mid points of sides BC,CA and AB of ΔABC
AP and BQ intersect at G
=> G is centroid of Triangle
=> AG/ AP = BG /BQ = CG /CR = 2/3
AG = 2 AP/3
BG = 2 BQ/3
CG = 2 CR /3
Adding all three
AG + BG + CG = 2 AP/3 + 2 BQ/3 + 2 CR /3
=> AG + BG + CG = (2/3) (AP + BQ + CR)
Similar Questions :
P,Q and R are respectively the mid points of sides BC,CA and AB of triangle ABC.PR and BQ meet atX. CR and PQ meet at Y. prove that XY=1/4BC
https://brainly.in/question/2086405
Prove that the centroid of a triangle divides the median in the ratio of 2:1
https://brainly.in/question/2271338
Similar questions