(p-q) – (p+q) pls do it fast
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Answer:
(p+q)(p-q)
=> px(p-q) + qx(p-q); (using Distributive Law)
=> p^2 - pq + qp - q^2
=> p^2 - q^2 (pq is same as qp so both nullify each other)
So, the correct answer is (p+q)x(p-q) = p^2 - q^2.
Answered by
0
Answer:
(p+q)(p-q)
=> px(p-q) + qx(p-q); (using Distributive Law)
=> p^2 - pq + qp - q^2
=> p^2 - q^2 (pq is same as qp so both nullify each other)
So, the correct answer is (p+q)x(p-q) = p^2 - q^2.
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