Question

p/q-q/p=4 find the value of p³/q³+q³/p³​

Answer 1

I think the required parameter would be p³/q³ - q³/p³, in case if I am wrong, let me know.

Answer:

76.

Step-by-step explanation:

The base of this question lies in a single formula; i.e.:

(a-b)³ = a³ - b³ - 3ab(a-b)

Now as we are given:

p/q-q/p = 4; and required parameter is 'p³/q³-q³/p³' ; thus, using formula as taking a = p/q and b = q/p:

(p/q-q/p)³ = (p/q)³ - (q/p)³ -3(p/q)(q/p)(p/q - q/p)

Now, by distribution of power( (a/b)^n = a^n/b^n) knowing p/q-q/p = 4; thus, substituting the values as:

4³ = p³/q³ - q³/p³ -3(p/q)(q/p)(4)

64 = p³/q³-q³/p³ - 12(1) .  .   .  .  (as p/q x q/p will cancel each other and will generate '1')

Thus;

p³/q³-q³/p³ = 64+12

p³/q³-q³/p³ = 76.