Math, asked by jayraj, 1 year ago

 p+q+r-=0,then what is value of p2/qr+q2/pr+r2/pq=?

Answers

Answered by lakshmidevi258
12
p+q+r=0
(p2(p)+q2(q)+r2(r))/pqr=2((p^2+q^2+r^2))/pqr=2((p+q+r)(pq+qr+rp))/pqr=2(0)=0
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