Question

p, q, r, s and t are five consecutive numbers in increasing order. lf r+ s + t + p = 101, then find the product of q and r

Answer 1

Let p=x
q=x+1,
r=x+2
s=x+3
t=x+4
Given
r+s+t+p=101
x+2+x+3+x+4+x=101
4x+9=101
4x=101-9
4x=92
x=92/4
x=23
Therefore
Product of q and r
=(x+1)(x+2)
=(23+1)(23+2)
=24*25
=6*4*25
=600

Answer 2

here ,let q =p+1 ,r = p+2 ,s = p+3 ,t = p+4
Now,p+p+2+p+3+p+4= 101
so,p = 23
hence,q= 24 and r = 25
q×r = 25×24= 600 ans