Question

p(q²+r²)-q(r²+p²)
factorize
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Answer 1

(P^2+q^2-r^2)^2 - 4p^2q^2

=(p^2+q^2-r^2)^2 - (2pq)^2

=(p^2+q^2-r^2+2pq)(p^2+q^2-r^2–2pq)

=(p^2+q^2+2pq-r^2)(p^2+q^2–2pq-r^2)

={(p+q)^2 - r^2}{(p-q)^2 - r^2}

=(p+q+r)(p+q-r)(p-q+r)(p-q-r)