Question

∆P QR ∼ ∆DEF for the correspondence P QR ↔ DEF. If 3P Q = 2DE, EF = 6 and P R = 8 find QR and DF.​

Answer 1

Answer:

ΔABC∼∆DEF (given)

2AB=DE, BC=6cm (given)

∠E=∠B and ∠D=∠A and ∠F=∠C

2AB=DE

⇒

DE

AB

=

2

1

Therefore,

DE

AB

=

EF

BC

2

1

=

EF

6