Question

Pʟs Sᴏʟᴠᴇ ᴛʜɪs ...... ​

Answer 1

Answer:

Angle CBA = 65°.

Step-by-step explanation:

Hello!!!

So, ATQ,

Angle ACD = 100° & Angle QAP = 35°.

Now,

If we see the line BD,

Angle BCA + Angle ACD = 180°. (linear pair )

so,

Angle BCA = 180 - 100

Angle BCA = 80° -------(1)

Now, we know that,

Angle BAC = Angle QAP (vertically opposite angles)

Angle BAC = 35°. --------(2)

Lastly,

In triangle ABC,

Angle CBA + Angle BCA + Angle BAC = 180° (angle sum property of triangle)

Angle CBA + 80° + 35° = 180° (from (1) & (2))

Angle CBA= 180 - 115

Angle CBA = 65°.

HOPE IT HELPS!!!!

Answer 2

Answer:

angle ACD =100 degree .

than , angle ACB=  [180 - 100 ]degree

                            =80 degree

angle QAP = 35 degree

                  =angle BAC [vertically opposite angle]

now ,

angle CBA = 180 degree  -   angle[ACB + BAC ]

                  =180degree  - [80 +35]degree

                  =[180 - 115] degree

                  =65 degree