p t 3-5root 2 is irrational
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let us assume that 3 -5√2 is a rational number
∴ 3- 5√2 = p / q (where q ≠ 0 and p & q are co-prime )
-5√2 = p / q - 3
-√2 = p / (5q) -3
√2 = - p +15 q / 5q
here, -p + 15 q / 5q is rational
but √2 is irrational
∵ irrational no.≠ irrational no.
∴ our assumption of taking 3 - 5√2 as rational no. was wrong
⇒3 - 5√2 is a irrational no.
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