Question

P(t) = 6t^3+3t^2+3t+18 is a multiple of (2t+3)

Answer 1

P(t)= 6t^3+3t^2+3t+18

= 3t^2(2t+3)-3t(2t+3)+6(2t+3)

= (2t+3)(3t^2-3t+6)

Hence, P(t) is a multiple of (2t+3).

I hope you will get it.

Answer 2

Answer:

hope... it will help u...