Question

p.T |b^2+c^2 a^2 a^2 b^2 c^2+a^2 b^2 c^2 c^2 a^2+b^2 | = 4a^2 b^2 c^2

Answer 1

a2+b 2+c2-ab-bc-ca=0
Multiply both sides with 2, we get
2( a + b + c – ab – bc – ca) = 0
2a + 2b + 2c – 2ab – 2bc – 2ca = 0
(a – 2ab + b ) + (b – 2bc + c ) +
(c – 2ca + a ) = 0
(a –b) + (b – c) + (c – a) = 0
Since the sum of square is zero then
each term should be zero
(a –b) = 0, (b – c) = 0, (c – a) = 0
(a –b) = 0, (b – c) = 0, (c – a) = 0
a = b, b = c, c = a
a = b = c.
therefore c+a/b=2
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