Question

p(t)=t^2+3t−10
Find the value of the polynomial when t=−2

Answer 1

Answer:

-20

Step-by-step explanation:

put t=(-2)

(-2)^2+ 3(-2)- 10

4-6-10

-20

Answer 2

Answer:

$p(2) = {2}^{2} + 3 \times 2 - 10 \\ 2p = 2 \times 2 + 3 \times 2 - 10 \\ 2p = 4 + 6 - 10 \\ 2p = 10 - 10 \\ 2p = 0 \\ p = \frac{0}{2} = 0 \\ so \: \: \: p \: = 0$

above is the equation

hope it will help you dear friend