Question

(p upon 3 + q upon 4)​

Answer 1

Answer:

47/10

Solution:

Let p^3 = q^4 = r^5 = s^6=k

So p=k^(1/3), q=k^(1/4), r=k^(1/5) and s=k^(1/6)

Thus log(base s)⁡pqr = log(base(k^(1/6) ))⁡ k^(1/3+1/4+1/5) =6 log(base k)⁡ k^((20+15+12)/60)=6×47/60 log(base k)⁡ k=47/10

Step-by-step explanation:

HOPE IT HELP YOU

PLEASE SUPPORT ME