Question

p varies directly as the square root of q .If p = 1 when q = 16. Find p when q = 9

PLEASE ANSWER THIS QUESTION...​

Answer 1

Answer:

Value of p = 3/4

Step-by-step explanation:

Given that p varies directly as the square root of q, therefore

= p ∝ $\sqrt{q}$

They have given that the value of p is 1 when q is 16

To find the value of p when q is 9

Let's take the given data as  $p_{1} = 1 , q_{1} = 16 , q_{2} = 9$

To find the value of $p_{2}$ consider

$\frac{p_{1} }{p_{2} } = \frac{\sqrt{q_{1} } }{\sqrt{q_{2} } }$

$\frac{1 }{p_{2} } = \frac{\sqrt{16 } }{\sqrt{9 } }$

$p_{2} = \frac{3}{4}$

Therefore the value of p is 3/4 when q is 9.