Question

p varies inversely as root q where p = 2 and q= 9 find p when q=9/4

Answer 1

Step-by-step explanation:

p∝1/√q

On removing the sign of proportionality,

=> p = k/√q

=> k = p√q

Thus, k = 2√9 = 2*3 = 6

If q = 9/4, k = 6

=> 6 = p*√[9/4]

=> 6 = 3p/2

Thus, p = 4

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