Question

p(x)=100x²-81 find the zero and verify the relationship between the zeros and the coefficient

Answer 1

100(x^2)-81=0 a=100, b=0, c=-81
100(x^2)=81
(x^2)=81/100
x=9/10 or -9/10
Let x and y be the roots
x+y= -b/a=0
x+y= 9/10-9/10=0
xy=c/a= -81/100
xy=(9/10)×(-9/10)= -81/100
Hence proved