Question

p(x)=12x²+18x-12;g(x)=x-1/2​

Answer 1

Answer:

$p(\frac{1}{2} )=0$

Step-by-step explanation:

$g(x)=x-\frac{1}{2}$

For g(x)=0

                    $g(x)=0\\ \\ x-\frac{1}{2}=0\\ \\ x=\frac{1}{2}$

For x=1

                        $p(\frac{1}{2} )=12(\frac{1}{2}) ^{2} +18(\frac{1}{2})-12\\ \\ p(\frac{1}{2} )=\frac{12}{4} +\frac{18}{2} -12\\ \\ p(\frac{1}{2} )=3+9-12\\ \\ p(\frac{1}{2} )=0$