Question

P(x)=2x^3-5x^2+ax+b x=2. X=0

Answer 1

Given,

P(x)=2x³-5x²+ax+b

when,x=2

P(2)=2*2³-5*2²+ax+b

=2*8-5*4+ax+b

=16-20+ax+b

=ax+b-4

again when, x=0

P(0)= 2*0³-5*0²+ax+b

=0-0+ax+b

=ax+b

Answer 2

Answer:

p(x) = 2x^3 - 5x^2 + ax+ b

2(0)^3 - 5(0)^2 + a(0) + b =0

b=0

2(2)^3 - 5(2)^2 + a(2) + b =0

16 - 20 + 2a + 0 = 0

2a = 4

a=4/2

a= 2

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