Question

p(x) = 2x³- 13x² + 17x + 12 , then find :
.
1) p(2) = [ ]

(a) 5 (b) 10 (c)15 (d)20
.
.
2) p(-3) = [ ]

a) -70 (b) -140 (c) -210 (d) -280
.
.
3) p(0) = [ ]

(a) 12 (b) 8 (c) 4 (d) 0
.
.
4) p(t) = [ ]

(a) 2t³- 13t² + 17t - 12
(b) 13t²+ 17t - 12
(c) 2t³ - 13t² - 17t - 12
(d) 2t³-13t² + 17t + 12

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Answer 1

p(2) = 2(2)^3 - 13(2)^2 +17(2) +12

=> 16 - 52 + 34 + 12

=> 10

p(-3) = 2(-3)^3 - 13(-3)^2 + 17(-3) + 12

=> - 54 - 117 - 51 + 12

=> ( - 210 )

p(0) = 2(0)^3 -13(0)^2 +17(0) + 12

=> 0 - 0 + 0 + 12

=> 12

p(t) = 2t³ - 13t² + 17t + 12