Question

p(x)=2x³+3x²+7x+9; at x=0, 1,Obtain the value of the given polynomial at the given values of x.

Answer 1

p(x)=2x³+3x²+7x+9; at x=0, 1.

at x = 0
P(0) = 2(0)³ + 3(0)² + 7(0) + 9
P(0) = 2 × 0 + 3 × 0 + 7 × 0 + 9
P(0) = 0 + 0 + 0 + 9
P(0) = 9
therefore, the value of the given polynomial at x = 0 is 9.

at x = 1
P(1) = 2(1)³ + 3(1)² + 7(1) + 9
P(1) = 2 + 3 + 7 + 9
P(1) = 5 + 7 + 9
P(1) = 12 + 9
P(1) = 21
therefore, the value of the given polynomial at x = 1 is 21

Answer 2

Hi ,

It is given that ,

p( x ) = 2x³ + 3x² + 7x + 9

i ) Value of p( x ) at x = 0 is

p( 0 ) = 2 × 0 + 3 × 0 + 7 × 0 + 9

p( 0 ) = 9

ii ) Value of p( x ) at x = 1 is

p( 1 ) = 2 × 1³ + 3 × 1² + 7 × 1 + 9

= 2 + 3 + 7 + 9

p( 1 ) = 21

I hope this helps you.

: )