p(x)=3x²+10x+7; at x=-3, 1,Obtain the value of the given polynomial at the given values of x.
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In the attachment I have answered
this problem.
The value of p(x) at x= -3 is obtained
by putting x =-3 in p(x).
The value is 4 and it has explained
detailly in the attachment .
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P(x) = 3x² + 10x + 7 ; at x = -3, 1 .
at x = -3
P(x) = 3x² + 10x + 7
P(-3) = 3(-3)² + 10(-3) + 7
P(-3) = 3 × 9 - 30 + 7
P(-3) = 27 + 7 - 30
P(-3) = 34 - 30
P(-3) = 4
hence, P(-3) = 4
at x = 1
P(1) = 3(1)² + 10(1) + 7
P(1) = 3 + 10 + 7
P(1) = 20
hence, P(1) = 20
at x = -3
P(x) = 3x² + 10x + 7
P(-3) = 3(-3)² + 10(-3) + 7
P(-3) = 3 × 9 - 30 + 7
P(-3) = 27 + 7 - 30
P(-3) = 34 - 30
P(-3) = 4
hence, P(-3) = 4
at x = 1
P(1) = 3(1)² + 10(1) + 7
P(1) = 3 + 10 + 7
P(1) = 20
hence, P(1) = 20
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