Question

p(x)=3x^2+x-1,q(x)=x+1​

Answer 1

p(x)=

$3 {x}^{2} + x - 1$

q(x)=x+1

x+1=0

x=-1

p(-1)=

$3( - 1 {}^{2} ) + 1 - 1$

3+1-1

4-1

3

Hence x+1 is not the factor of the following polynomial.

Hope It will Help you..

Answer 2

ANSWER

QUOTIENT = 3x - 2

REMAINDER = 1

EXPLANATION............

3x - 2

_____________

x + 1 ) 3x² + x - 1

3x² + 3x

(-) (-)

_____________

- 2x - 1

- 2x - 2

(+) (+)

_____________

1

HERE'S YOUR ANSWER.....!

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