Question

p(x)=3x^3-x^2-3x+1; g(x)=x+1

Answer 1

x + 1 = 0
x = -1

NOW, PUTTING THIS VALUE

3(-1)^3 - (-1)^2 - 3(-1) + 1
- 3 - 1 + 3 + 1
0 Answer

Answer 2

$\textbf {Solution:}$

Given:

g(x) = x + 1 = 0

=> x = -1

p(x) = 3x³ - x² - 3x + 1.

p(-1) = 3 × (-1)³ - (-1)² - 3 × (-1) + 1

p(-1) = -3 - 1 + 3 +1

p(-1) = 0


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$\textbf{THANK YOU!!}$