Question

P(X) = 4X2 + 5X− 8, then find the zeroes

Answer 1

Answer:

❤ Hello ❤

Step-by-step explanation:

$4 {x}^{2} + 5x - 8 \\ = > quadratic \: formula \\ = > \frac{ - b + \sqrt{ {b}^{2} - 4ac} }{2a} \\ put \: the \: values \: of \: ab \: \\ and \: c \: and \: find \\ \: your \: answer$

hope it's help u

Answer 2

Step-by-step explanation:

4x²+5x-8

By using Quadratic Formula

D = √b²- 4ac

D = √ (5)²-4*4*-8

D = √ 25 + 128

D = √ 153

D = 12.36

When we take positive integer

x = - b + D/2a

x = -5+12.36/2*4

x = 7.36/8

x = 0.92

x = 92/100

x = 23/25

When we take negative integer

x = -b - D/2a

x = - 5 - 12.36/2*4

x = - 17.36/8

x = 2.17

x = 217/100

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