Question

P(x)=4x³-2x²-5x+7,find p(1),p(0)
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Answer 1

Answer:

for x=1

p(1)=4-2-5+7

=4

for P(0)=7

Answer 2

Answer:

here p(1)

$p(x) = {} {4x}^{3} - {2x}^{2} - 5x + 4 \\ p(x) = 4 \times {1}^{3} - 2 \times {1}^{2} - 5 \times 1 + 7 \\ = 4 \times 1 - 2 \times 1 - 5 + 7 \\ = 4 - 2 - 5 + 7 \\ = 2 - 5 - 7 \\ = - 3 - 7 \\ = - 10$

again p(0)

$p(x) = 4 {x}^{3} - 2 {x}^{2} - 5x + 4 \\ = 4 \times {0}^{3} - 2 \times {0}^{2} - 5 \times 0 + 4 \\ = 4 \times 0 - 2 \times 0 - 5 \times 0 + 4 \\ = 0 - 0 - 0 + 4 \\ = 4$

May it help you...... :)....